Hitunglah volume kerucut dengan diameter 21 dan tinggi. 49 ! jawab
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Volume
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[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{aligned} \sf volume &=\sf \frac{1}{3} \pi {r}^{2} t\\ \sf &=\sf \frac{1}{3} \times \frac{22}{\cancel{7 \: }} \times 10,5 \times 10,5 \times\cancel{49}\\ \sf &= \sf \frac{1}{3} \times 22 \times 110,25 \times 7\\ \sf &= \sf \frac{1}{3} \times 16.978,5 \\ & =\sf{5.659,5 \: {cm}^{3}} \end{aligned}\end{gathered}\end{gathered}\end{gathered}[/tex]
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